Question

If the area of a square inscribed in a circle is 90 sq cm , find the diameter of the circle

Answer 1

Heya !!

Here's your answer..
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Area of square = 90 cm²

Area of square = s²

s² = 90

s = 3√10 cm

Diagonal of square is equal to Diameter of circle.

∆BDC is right angled triangle.

BD² = BC² + DC²

BD² = ( 3√10 )² + ( 3√10 )²

BD² = 90 + 90

BD² = 180

BD = 6√5 cm

Diameter of circle is 6√5 cm.
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Hope it helps..
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Answer 2

Answer:

Area of square = 90 cm²

Area of square = s²

s² = 90

s = 3√10 cm

Diagonal of square is equal to Diameter of circle.

∆BDC is right angled triangle.

BD² = BC² + DC²

BD² = ( 3√10 )² + ( 3√10 )²

BD² = 90 + 90

BD² = 180

BD = 6√5 cm

Diameter of circle is 6√5 cm.