If the area of a square is 225 cm^2 , find (a) it's perimeter , and (b) the length of a diagonal.
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Answers
Answered by
1
hai
here is Ur ans
A*)=>perimeter
Ais the area of the length
s is the length of the side of square
substitute and slove for given:-
=>225 cm^2=s^2
we can take square root of each side of the equation givung:-
=> √225 cm^2 = s
=>15cm=s
=>s=15cm
formula for perimeter of square =
=>p=4s
where p is perimeter of square .
s is the length of side of a square
substituting from s and from the solution for
the previous formula and calculate p gives :
=>p= 4×15cm
=>p=60cm
B*)=>diagonal
=>a^2 +b^2 =^2
=>a×b=a^2
=>x×x=x^2 -225
=>√x^2 - √225
=>x=15
by using pythogarus
=>a^2 +b^2-c^2
=> x^2 +x^2 =c^2
=>x^2 +x^2 =2x
=>c^2 = 2x
=>c=√ 2x^2
=>c=x√2
=>x= 15
=>c= 15√2
=>c=21.2132034
hope my ans help full mate
here is Ur ans
A*)=>perimeter
Ais the area of the length
s is the length of the side of square
substitute and slove for given:-
=>225 cm^2=s^2
we can take square root of each side of the equation givung:-
=> √225 cm^2 = s
=>15cm=s
=>s=15cm
formula for perimeter of square =
=>p=4s
where p is perimeter of square .
s is the length of side of a square
substituting from s and from the solution for
the previous formula and calculate p gives :
=>p= 4×15cm
=>p=60cm
B*)=>diagonal
=>a^2 +b^2 =^2
=>a×b=a^2
=>x×x=x^2 -225
=>√x^2 - √225
=>x=15
by using pythogarus
=>a^2 +b^2-c^2
=> x^2 +x^2 =c^2
=>x^2 +x^2 =2x
=>c^2 = 2x
=>c=√ 2x^2
=>c=x√2
=>x= 15
=>c= 15√2
=>c=21.2132034
hope my ans help full mate
Answered by
5
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