Question

If the area of a trapezium is 28 m2, and two parallel sides are 8 m and 60 dm
respectively, find the altitude,​

Answer 1

Answer:

area = 28 m sq.

sum of parallel side = (8m + 60dm) or(8m+6m)

hence

\begin{gathered}area \: = \frac{1}{2} \times (sum \: of || side) \times h \\ \\ 28 = \frac{1}{2} ( 8+ 6) \times h \\ \\ 28 = \frac{1}{2} \times 14 \times h \\ \\ 28 = 7 \times h \\ \\ h = \frac{28}{7} \\ \\ h = 4\end{gathered}

area=

2

1

×(sumof∣∣side)×h

28=

2

1

(8+6)×h

28=

2

1

×14×h

28=7×h

h=

7

28

h=4

Answer 2

$\huge\underline\mathfrak\red{ϙᴜᴇsᴛɪᴏɴ}$

If the area of a trapezium is 28 m2, and two parallel sides are 8 m and 60 dm respectively, find the altitude.

$\huge\bold\red{Given}$

The length of parallel sides of the trapezium are 8m and 60dm respectively.

$\sf{we~ know~ that~ 10dm = 1m}$

$\sf{.°.60dm =}$ $\frac{60}{10}$$\sf{= 6m}$

$\large\sf{we ~have~ to ~find ~the ~altitude~ of ~the~ trapezium.}$

formula for the area of trapezium is $\frac{1}{2}$ × h ( b1 + b2 ) where "h" is the altitude and b1 and b2 are the parallel sides of the trapezium.

area of the trapezium = 28m²

$\longrightarrow$ $\frac{1}{2}$ × h ( b1 + b2 ) = 28m²

$\longrightarrow$ $\sf{h ( 8 + 6 )=}$ $\frac{28}{1}$× $\frac{2}{1}$

$\longrightarrow$ $\sf{h ( 8 + 6 ) =}$ $\frac{51}{1}$

$\longrightarrow$ $\sf{14h = 56}$

$\longrightarrow$ $\sf{h =}$$\frac{56}{14}$

$\longrightarrow$ $\sf{ h = 4}$

$\large\mathfrak\pink{♡αɳรωεɾ♡}$

Hence, the altitude of the trapezium is 4m.