Question

If the area of a trapezium is 28m sq. ,two parallel sides are 8m and 60 dm respectively, find the altitude.

Answer 1

given

area = 28 m sq.

sum of parallel side = (8m + 60dm) or(8m+6m)

hence

$area \: = \frac{1}{2} \times (sum \: of || side) \times h \\ \\ 28 = \frac{1}{2} ( 8+ 6) \times h \\ \\ 28 = \frac{1}{2} \times 14 \times h \\ \\ 28 = 7 \times h \\ \\ h = \frac{28}{7} \\ \\ h = 4$

therefore altitude is 4 m






thank you

Answer 2

$\bf \large \it{Hey \: User!!!}$

given the length of parallel sides of the trapezium are 8m and 60dm respectively.

we know that 10dm = 1m

therefore 60dm = 60/10 = 6m

we have to find the altitude of the trapezium.

formula for the area of trapezium is 1/2 × h ( b1 + b2 ) where "h" is the altitude and b1 and b2 are the parallel sides of the trapezium.

area of the trapezium = 28m²
>> 1/2 × h ( b1 + b2 ) = 28m²
>> h ( 8 + 6 ) = 28/1 × 2/1
>> h ( 8 + 6 ) = 56/1
>> 14h = 56
>> h = 56/14
>> h = 4

hence, the altitude of the trapezium is 4m.

$\bf \large \it{Cheers!!!}$