Question

If the area of a trapezium is 56 sq. cm and one of its parallel sides is 6 cm, find the other parallel si
if its altitude is 8 cm.​

Answer 1

Given :

• Area of trapezium = 56 cm²
• One parallel side = 6 cm
• Altitude of trapezium = 8 cm

To find :

• Other parallel side of trapezium

According to the question,

As we know,

➞ Area of trapezium = ½ × sum of parallel × height

• Let the other parallel side be x.

➞ 56 = ½ × (6 + x) × 8

➞ 56 = (6 + x) × 4

➞ 56 = 24 + 4x

➞ 56 - 24 = 4x

➞ 32 = 4x

➞ 32 ÷ 4 = x

➞ 8 = x

• So,the other parallel side is 8 cm.

____________________

MORE FORMULAS :-

• Area of rectangle = Length × Breadth

• Area of square = Side × Side

• Surface area of a cube = 6a²

• Surface area of cuboid = 2(lb + bh + hl)

• Volume of cuboid = l × b × h

• Total surface area of a hemisphere = 3πr²

• Curved surface area of a cone = πrl

• Total surface area of a cylinder = 2πr(r + h)

Answer 2

Answer:

Given :-

• The area of a trapezium is 56 cm² and one it's parallel sides is 6 cm and its altitude is 8 cm.

To Find :-

• What is the other parallel side.

Formula Used :-

✦ Area of trapezium = ½ × Sum of parallel × Altitude ✦

Solution :-

Let, the other parallel side be x

Given :

• Area = 56 cm²
• One parallel = 6 cm
• Altitude = 8 cm

According to the question by using the formula we get,

⇒ 56 = ½ × (6 + x) × 8

⇒ 56 = ½ × 48 + 8x

⇒ 56 × 2 = 48 + 8x

⇒ 112 = 48 + 8x

⇒ 112 - 48 = 8x

⇒ 64 = 8x

⇒ 64 ÷ 8 = x

⇒ 8 = x

➠ x = 8

∴ The other parallel side is 8 cm .

Let's Verify :-

↦ 56 = ½ × (6 + x) × 8

Put x = 8, we get

↦ 56 = ½ × (6 + 8) × 8

↦ 56 = ½ × (14) × 8

↦ 56 = ½ × 112

↦ 56 = 56

➥ LHS = RHS

Hence, Verified ✔