Question

If the area of a triangle is 24cm' and attitude is
18cm , what is the length of its base?​

Answer 1

Answer:

2.6cm

Step-by-step explanation:

area of triangle=1/2length ×alitude

24 =1/2×length×18

length=24/9=2.6cm

Answer 2

AnswEr-:

$\dag{\underline {\mathrm{Base\:of\:Triangle\:is\:2.67cm\;[Approx]}}}$

Explanation-:

• $\mathrm{Given-:}$

• The area of a triangle is 24 cm²

• The altitude or height of triangle is 18 cm

• $\mathrm{To\:Find-:}$

• The length of base of triangle.

• $\dag{\underline {\mathrm{Solution \:of\:question-:}}}$

• $\underbrace {\sf{Understanding \:the\:Concept-:\:}}$

• We have to find the base of triangle.

• For this we have to put the known or given Values in the formula for Area of Triangle then we can get the Base of triangle.

As We know that ,

• $\underline{\boxed{\star{\sf{\blue{ Area_{(Triangle)}  \: = \: \dfrac{1}{2} \times Base \times Height }}}}}$

• $\mathrm{Here-:}$

• The area of a triangle is 24 cm²
• The altitude or height of triangle is 18 cm

• The base of triangle is ??

Now by putting known Values in the Formula for Area of Triangle-:

• $\longrightarrow{\sf{Area \:of\:\triangle \:= \dfrac{1}{2} \times 18 \times Base = 24 cm^{2}}}$

• $\longrightarrow{\sf{ \dfrac{1}{\cancel {2}} \times \cancel {18} \times Base = 24 cm^{2}}}$

• $\longrightarrow{\sf{ 9 \times Base = 24 cm^{2}}}$

• $\longrightarrow{\sf{ Base = \dfrac{24}{9} }}$

• $\longrightarrow{\sf{ Base = \dfrac{\cancel {24}}{\cancel {9}} }}$

• $\longrightarrow{\sf{ Base = 2.67cm\: [ Approx]}}$

Hence ,

• $\dag{\underline {\mathrm{Base\:of\:Triangle\:is\:2.67cm\;[Approx]}}}$

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♡ Verification-:

• $\underline{\boxed{\star{\sf{\blue{ Area_{(Triangle)}  \: = \: \dfrac{1}{2} \times Base \times Height }}}}}$

$\mathrm{Here-:}$

• The area of a triangle is 24 cm²

• The altitude or height of triangle is 18 cm

• The base of triangle is 2.67 cm

Now by putting known Values in the Formula for Area of Triangle-:

• $\longrightarrow{\sf{ \dfrac{1}{2} \times 18 \times Base = 24 cm^{2}}}$

• $\longrightarrow{\sf{ \dfrac{1}{\cancel {2}} \times \cancel {18} \times 2.67 = 24 cm^{2}}}$

• $\longrightarrow{\sf{ 9 \times 2.67 = 24 cm^{2}}}$

• $\longrightarrow{\sf{ 24.03cm^{2} = 24 cm^{2}}}$

By doing round off of 24.03 cm² to the nearest tenth then it is equal to the 24 cm²

• $\longrightarrow{\sf{ 24cm^{2} = 24 cm^{2}}}$

Therefore,

• $\dag{\underline {\mathrm{LHS = RHS}}}$

• $\dag{\underline {\mathrm{Hence\:, Verified!}}}$

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