Math, asked by hell81032006, 5 months ago

If the area of a triangle with base 27cm is equal to area of a square with
side 18cm. The altitude of the triangle is *​

Answers

Answered by sangeeta343
1

Answer:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

A=

s(s−a)(s−b)(s−c)

where

s=

2

a+b+c

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

s=

2

18+24+30

=36

A=

36(36−18)(36−24)(36−30)

A=

36×18×12×6

A=

216×216

=216 cm

2

Smallest side =18 cm

Area of the triangle =

2

1

×base×altitude=216

2

1

×18× altitude=216

Altitude =

9

216

=24 cm

Step-by-step explanation:

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Answered by Anonymous
0
AnSwEr -:

Height or Altitude of triangle-: 24 cm

_____________________________
Explanation-:

Area of square = s x s

S= length of side of a square

Area of triangle-: 1/2 x b x h

B= base

H= height or altitude

_____________________________

Given ,

S= 18 cm

Area of square = s x s

S= length of side of a square = 18 cm

18 cm x 18 cm

= 324 cm^2

Area of square = 324 cm^2

According to the question-:

Area of square = Area of triangle

Area of triangle-: 1/2 x b x h

B= base =27 cm

H= height or altitude = ??

Area of triangle = 324 cm^2


1/2 x 27 x h = 324 cm^2

1/2 x H = 324 / 7

1/2 x H = 12

H= 12 x 2 = 24

H= 24

Height or Altitude of triangle-: 24 cm

_______________________________

Some other formulas -:

Area of square = s x s

S= length of side of a square

Area of triangle-: 1/2 x b x h

B= base

H= height or altitude

Area of Rectangle-: l x b

L= length

B= breadth

_____________________________


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