Question

If the area of an equilateral triangle is 16 cm2 , then the perimeter of the triangle is?​

Answer 1

Step-by-step explanation:

Given;

We know that

tex] => ( \sqrt{3} \div 4) \times (side) {}^{2} = 16 \\ [/tex]

$area \: of \: triangle \: \\ => ( \sqrt{3 } \div 4) \times \ (side {}^{2} )$

$= > (side)^{2} = 16 \times (4 \div \sqrt{3} ) \\ = > (side) {}^{2} = 16 \times 2.31 \: approx \\ = > (side) {}^{2} = 36.96 \: approx \\ = > side = 6.07 \\ therefore \: perimetre \\ = > 3 \times (6.07) \\ = > 18.20 \: cm \: \: \: approx.$

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Answer 2

Answer:

10.4cm

Step-by-step explanation:

Area = 16cm²

Area of a equilateral triangle = √3/4  a²  (where a = side)

First, lets find the side of the triangle so it'll be easy to find the area.

Side of an equilateral triangle = 2/3  3¾  √A  (where A = area)

= 2/3  3¾  √16

= 2/3  3¾  √4  (shortened root)

= 6.08cm

Now, we have the side. So lets find out the area.

Area of a equilateral triangle = √3/4  a²  (where a = side)

= √3/4  a² = 1.73 / 4 x a

= 0.43  x  4 6.08

= 0.43 x 24.3

= 10.4cm