Question

if the area of an equilateral triangle is 16 root 3,then find its perimeter

Answer 1

$\frac{ \sqrt{3} {a}^{2} }{4} = 16\sqrt{3} \\ \\ \frac{ \sqrt{3} {a}^{2} }{ \sqrt{3} } = 16 \times 4 \\ \\ {a}^{2} = 64 \\ \\ a = \sqrt{64 } \\ \\ a = 8 \: unit$
side of equilateral triangle = 8 unit.

perimeter of equilateral triangle

= 3 a

= 3 ×8

= 24 unit.

Answer 2

This is how you can do that sum....Hope it helps!!!!!