Question

If the area of an isosceles right angled triangle is 32cm×cm,then the length of its longest altitude is equal to

Answer 1

In right isoceles triangle longest altitude is equal to one of the equal side

Answer 2

Answer:

8 cm

Step-by-step explanation:

Given :The area of an isosceles right angled triangle is 32 sq.cm

To Find : the length of its longest altitude is equal to

Solution:

The given triangle is isosceles

So, Perpendicular = Base

Let the base be x

So,  Perpendicular = Base =x

Area of triangle = $\frac{1}{2} \times Base \times Height$

                         = $\frac{1}{2} \times x \times x$

                         = $\frac{1}{2}x^2$

Since we are given that The area of an isosceles right angled triangle is 32 sq.cm

So,  $\frac{1}{2}x^2=32$

 $x^2=64$

$x=\sqrt{64}$

$x=8$

So, the length of its longest altitude is equal to 8 cm