if the area of an isosceles right angled triangle is 8cm² then what is the perimeter of the triangle
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Hi !
base = b
altitude = h
A.T.Q.,
b = a
we have to find hypotenuse
We know that,
Area of triangle = 1/2bh
8 = 1/2bh
but , b = h
8 = 1/2b*b
8 = 1/2b²
b² = 8*2
b² = 16
b = 4 cm
we know that,
b = h = 4 cm
also ,
hypotenuse² = b² + h²
= 16+ 16
= 32
hypotenuse = √32 cm
= 4√2 cm
Perimeter = hypotenuse + b + h
= 4 √2 + 4 + 4
= 4√2 + 8
= 4(√2 + 2) cm
base = b
altitude = h
A.T.Q.,
b = a
we have to find hypotenuse
We know that,
Area of triangle = 1/2bh
8 = 1/2bh
but , b = h
8 = 1/2b*b
8 = 1/2b²
b² = 8*2
b² = 16
b = 4 cm
we know that,
b = h = 4 cm
also ,
hypotenuse² = b² + h²
= 16+ 16
= 32
hypotenuse = √32 cm
= 4√2 cm
Perimeter = hypotenuse + b + h
= 4 √2 + 4 + 4
= 4√2 + 8
= 4(√2 + 2) cm
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