Math, asked by singhprinceke, 24 days ago

If the area of circle is 616cm²,find it's circumstances.

Answers

Answered by dandiwaljagmeet77
1

Given,

πr 2 =616

r 2 = 22/616×7

r 2=28×7

r=14

Therefore, Circumference = 2πr=2×7/22×14=88 cm

Answered by duavansh04
0

Answer:

616 = πr^2

616 = πr^2616x 7 = r^2

616 = πr^2616x 7 = r^2÷ 22

616 = πr^2616x 7 = r^2÷ 22r^2 = 196

616 = πr^2616x 7 = r^2÷ 22r^2 = 196 r = 14

616 = πr^2616x 7 = r^2÷ 22r^2 = 196 r = 14 circumference = 2πr .

616 = πr^2616x 7 = r^2÷ 22r^2 = 196 r = 14 circumference = 2πr .= 2 x 22/7 x 14

616 = πr^2616x 7 = r^2÷ 22r^2 = 196 r = 14 circumference = 2πr .= 2 x 22/7 x 14= 88 cm.

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