If the area of circular bases of a frustum obtained fro a cone is 4cm^2 and 16cm^2 and if 15cm
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Answer:
Volume of frustum = 2.08 cm³
Step-by-step explanation:
The ares of the circular bases of a frustum of a cone are 4 cm² and 9 cm²
So, let the radius of the upper base be 'R' and radius of the lower base be 'r'.
Now, Area of upper circular base = π·R²
⇒ 9 = π·R²
⇒ R = 1.69 cm
Area of lower circular base = π·r²
⇒ 4 = π·r²
⇒ r = 1.13 cm
r = 1.13 cm and R = 1.69 cm and height (h) = 12 cm
Now, we know that slant height of frustum, l = √h²+(R - r)² where h is the height of the frustum.
l = √h²+(1.69 - 1.13)²
l² = 12² + 0.31
l² = 144 + 0.31
l² = 144.31
l = 12.01 cm
Hence, Volume of frustum = 2.08 cm³..
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