if the area of equilateral triange is 81underroot 3 find its perimeter
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√3/4 a²=81√3,
then
a²=81×4,
a=√(81×4),
a=9×2=18 cm
therefore
perimeter of the triangle=3×a=3×18=54
then
a²=81×4,
a=√(81×4),
a=9×2=18 cm
therefore
perimeter of the triangle=3×a=3×18=54
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