Question

if the area of rectangle is 200 sq.m and the length is 20 m, find the perimeter of the rectangle

Answer 1

Hey...!!!

Area of rectangle = 200 sq. m
Length = 20 m
So, let the breadth be x
Then,
Length * breath = area
20 * x = 200
X = 200/20
X = 10
So,breadth = 10 m

Perimeter = 2 (Length + Breadth)
= 2( 20 + 10)
= 2 * 30
= 60 m
So, the perimeter of the rectangle = 60 m

Hope it helps...!!!

Answer 2

area of rectangle= length×breadth
200=20×breadth
$breadth = \frac{200}{20}$
breadth=10m

perimeter=2(l+b)
=2×(20+10)
=2×30
=60m