If the area of rectangle is 24cm and its perimeter is 22 cm then its sides in meter are
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Hiii friend,
Let the Length and Breadth be X and Y m
Area of rectangle = 24 cm
Length × Breadth = 24
X × Y = 24...(1)
Again,
Perimeter of rectangle = 22 cm
2(L+B) = 22
Length + Breadth = 22/2
Length + Breadth = 11
X + Y = 11......(2)
From equation (1) we get,
X × Y = 24
X = 24/Y......(3)
Putting the value of X in equation (2)
X + Y = 11
24/Y + Y = 11
24 + Y² = 11Y
Y²-11+24 = 0
Y² -6Y -4Y +24 = 0
Y(Y-6) -4(Y-6) = 0
(Y-6) (Y-4) = 0
(Y-6) = 0. OR (Y-4) = 0
Y = 6 Or Y = 4
When Y = 6
X = 24/Y = 24/6 = 4 cm
When Y = 4 cm
X = 24/Y = 24/4 = 6 cm
Therefore,
When Y = 6
Then,
The breadth of rectangle = Y = 6 cm
And,
Length of the rectangle = X = 4 cm
When Y = 4 cm
Then,
breadth of rectangle = Y = 4 cm
And,
length of rectangle = X = 6 cm
HOPE IT WILL HELP YOU..... :-)
Let the Length and Breadth be X and Y m
Area of rectangle = 24 cm
Length × Breadth = 24
X × Y = 24...(1)
Again,
Perimeter of rectangle = 22 cm
2(L+B) = 22
Length + Breadth = 22/2
Length + Breadth = 11
X + Y = 11......(2)
From equation (1) we get,
X × Y = 24
X = 24/Y......(3)
Putting the value of X in equation (2)
X + Y = 11
24/Y + Y = 11
24 + Y² = 11Y
Y²-11+24 = 0
Y² -6Y -4Y +24 = 0
Y(Y-6) -4(Y-6) = 0
(Y-6) (Y-4) = 0
(Y-6) = 0. OR (Y-4) = 0
Y = 6 Or Y = 4
When Y = 6
X = 24/Y = 24/6 = 4 cm
When Y = 4 cm
X = 24/Y = 24/4 = 6 cm
Therefore,
When Y = 6
Then,
The breadth of rectangle = Y = 6 cm
And,
Length of the rectangle = X = 4 cm
When Y = 4 cm
Then,
breadth of rectangle = Y = 4 cm
And,
length of rectangle = X = 6 cm
HOPE IT WILL HELP YOU..... :-)
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