Math, asked by KSHITIJBUNNY, 1 year ago

if the area of rhombus is 96cm^2

and one of its diognal is 16cm find its perimeter

Answers

Answered by jarpana2003
3

Answer:

Step-by-step explanation:

area of rhombus = 1/2 d1 d2

96= 1/2 x 16 x d2

d2= 12 cm

perimeter is given by 2(d1^2 + d2^2)^1/2

2(144+256)^1/2

2(400)^1/2

2x20=40 cm


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Answered by Anonymous
2
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