if the area of rhombus is 96cm^2
and one of its diognal is 16cm find its perimeter
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Answer:
Step-by-step explanation:
area of rhombus = 1/2 d1 d2
96= 1/2 x 16 x d2
d2= 12 cm
perimeter is given by 2(d1^2 + d2^2)^1/2
2(144+256)^1/2
2(400)^1/2
2x20=40 cm
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