Question

If the area of the equalateral triangle is 8root3 cm^3 then its perimeter is

Answer 1

$\frac{ \sqrt{3} }{4} {a}^{2} = 8 \sqrt{3} \\ a = \sqrt{32} \\ a = 4 \sqrt{2} \\ perimeter = 3a \\ p = 3 \times 4 \sqrt{2} \\ p = 12 \sqrt{2}$
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Answer 2

Hi friend, Harish here.

Here is your answer:

Let the side of equilateral triangle be " a ".

Then we know that,

⇒ $Area\ of\ triangle = \frac{ \sqrt{3} a^{2}}{4}$

⇒  $8 \sqrt{3} = \frac{ \sqrt{3} a^{2}}{4}$

⇒  $a^{2} = 8\times 4 = 32$

⇒  $a = \sqrt{32} = 4 \sqrt{2}$

Then ,

perimeter = 3 × a 

⇒ 3 × (4√2) 

⇒ 12√2 cm.

Therefore the perimeter is 12√2 cm. 
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Hope my answer is helpful to you.