Question

If the area of the rhombus is 24 cm2, one of the diagonalis 8 cm .find it perimeter

Answer 1

Area of rhombus=d¹d²/2
24=4d²
: d2=8
Perimeter=4×4√2
=16√2

Answer 2

Hey there!
Area = d1 ( d2)

Now, given d1 = 8 .
Area = 1/2d1 ( d2) = 8(d2) = 24
d2 = 48/8 = 6

Now, (Diagonal/2 )² + (Diagonal/2)² = Side²

8/2² + (6/2)² = Side²
4² + (3)² = side²
Side² = 16 + 9 = 25
Side = √25 = 5cm .

Perimeter = 4(5)cm = 20 cm.

Hope helped!