Question

If the area of the rhombus is 96 and one of its diagonal is 16 then find the length of side of the rhombus

Answer 1

Given, Let us consider d1 = 16 Area of a Rhombus = 1/2 * d1 * d2 = 96 0.5 * 16 * d2 = 96 d2 = 96 / 8 = 12 Perimeter of a Rhombus when d1 and d2 are given p = √ ( d1² + d2² ) = √ ( 16² + 12² ) = √ ( 256 + 144 ) p = √ 400 p = 200cm