If the area of the triangle with vertices (a, 5), (6,7) and (2,3) is 10, a = _______ (a> 0).
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Answer:
answer:- a=9
Step-by-step explanation:
area of triangle= 1/2(xone( y two -y three) + x two( y three - y one )+ xthree ( y one - y two)
= 10 = 1/2 ( a(7-3)+6(3-5)+2(5-7))
=10×2=7a-3a+6(-2)+2(-2)
=20=4a-12-4
=20=4a-16
=20+16=4a
=4a=36
=a=36/4
=a=9
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