Question

If the area of trapezium with parallel sides of lengths 30 cm and 23 cm respectively is 265sqcm, what is its height?​

Answer 1

Answer:

The area of trapezium = 1

                                        2  * sum of parallel sides * height

                                1

            265    =       2  * 30+23 * h

            265 =  1

                        2 * 53*h  ⇒  h = 265 * 2

                                                       53

                                                 = 530

                                                     53

                                               Height = 10

           

Answer 2

$\huge\sf\pink{question}$

if the area of trapezium with parallel sides of lengths 30 cm and 23 cm respectively is 265sqcm, what is its height?

$\huge\sf\red{Answer}$

$\huge\sf\gray{Given:}$

Area of trapezium = 265 sq cm.

Length of one parallel side = 30 cm

Length of the other parallel side = 23 cm

Sum of parallel side = (30 + 23) = 53 cm

Height =

2 × Area of trapezium

Sum of Parallel sides

⇒ Height = 10 cm