Question

which of the following is the once of a rhombus
a. 1/2( sum of it's diagonals)
b.product of it's diagonals
c.2(product of it's diagonals)​

Answer 1

Answer:

for finding the area of rhombus multiply the length of both diagonals and divide it by 2

$area = (p \times q) \div 2$

p and q=length of diagonals

for finding perimeter of rhombus multiply it's side by 4

$perimeter = 4 \times a$

a=side

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Answer 2

Answer:

A ) 1 / 2 ( sum of it's diagonals)

Step-by-step explanation:

A ) 1 / 2 ( sum of it's diagonals)

Area of a rhombus = pq/2

Where p and q are diagonals.

Rhombus

A rhombus is a special case of a parallelogram, and it is a four-sided quadrilateral. In a rhombus, opposite sides are parallel and the opposite angles are equal. Moreover, all the sides of a rhombus are equal in length, and the diagonals bisect each other at right angles. The area of a rhombus can be defined as the amount of space enclosed by a rhombus in a two-dimensional space.

Area of Rhombus

Using Diagonals (A) = ½ × d1 × d2

Using Trigonometry (A) = b2 × Sin(a)

Using Base and Height (A) = b × h

Where,

d1 = length of diagonal 1

d2 = length of diagonal 2

b = length of any side

h = height of rhombus

a = measure of any interior angle

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