Question

If the area of triangle ABC formed by A(x,y),B(1,2),C(2,1) is 6 square units then find the relations between x and y with solv

Answer 1

according to your question , i have answered

Answer 2

Answer:

The relation between x and y is $x+y=15$. The sum of x and y is 15.

Step-by-step explanation:

The vertices of triangle ABC are A(x,y),B(1,2),C(2,1).

The area of a triangle is

$A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

The area of triangle ABC is

$A=\frac{1}{2}[x(2-1)+1(1-y)+2(y-2)]$

$A=\frac{1}{2}[x+1-y+2y-4]$

$A=\frac{1}{2}[x+y-3]$

It is given that the area of triangle ABC is 6 square units.

$6=\frac{1}{2}[x+y-3]$

$12=x+y-3$

$12+3=x+y$

$x+y=15$

Therefore the relation between x and y is $x+y=15$. The sum of x and y is 15.