if the area of triangle ABC formed by A (x, y) B(1,2) C (2,3) is 6sq units then find the relations between X and Y.
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mansi57:
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area=6
1\2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=6
x(2-3)+1(3-y)+2(y-2)=12
2x-3x+3-y+2y-4=12
-x+y=12+1
x-y=-13
x-y+13=0
1\2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=6
x(2-3)+1(3-y)+2(y-2)=12
2x-3x+3-y+2y-4=12
-x+y=12+1
x-y=-13
x-y+13=0
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