if the area of triangle ABC is equal to area of square of side length 6 CM then what is the length of the attitude of AB, where AB =9CM
A)18CM
B)14CM
C)12CM
D)8CM
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Side of square = 6 cm
Area of square = 6^2 cm^2
=36 cm^2
Area of square=Area of rectangle
Let the breadth be B
36 cm^2=9 cm ×B
36 cm^2/9 cm =B
B =4 cm
Area of square = 6^2 cm^2
=36 cm^2
Area of square=Area of rectangle
Let the breadth be B
36 cm^2=9 cm ×B
36 cm^2/9 cm =B
B =4 cm
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