If the areas of two triangles ABC and PQR are in the ratio 9:16 and BC=4.5cm, what is the length of QR?
Answers
Answered by
79
Both triangle must be similar triangles.
Then,
(Area)₁/(Area)₂ = (side)₁²/(side)₂²
⇒9/16 = (4.5)²/(side)₂²
⇒(side)₂ =[ (4.5)×4]/3
= 6 cm
∴QR = 6 cm
Then,
(Area)₁/(Area)₂ = (side)₁²/(side)₂²
⇒9/16 = (4.5)²/(side)₂²
⇒(side)₂ =[ (4.5)×4]/3
= 6 cm
∴QR = 6 cm
Answered by
26
Answer:
Step-by-step explanation:
ar(ABC)/ar(PQR)=(BC)×(BC)/(QR×QR)
9/16=4.5×4.5/QR×QR
QR×QR=4.5×4.5×16÷9
QR=√4.5×4.5×16÷9
QR=4.5×4/3
QR=18.0÷3
:- QR=6cm
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