If the arms of one of the angles are respectively parallel to the arms of another angle show that the two angles are either equal or supplementary
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here is your answer:
BA || ED and BC is a traversal,
∴ ∠EGB = ∠ABC (these are the alternate angles)
BC || EF and DE is a traversal,
∠DEF + ∠EGB = 180° (these are the co interior angles)
∠DEF + ∠ABC = 180° (∴∠EGB = ∠ABC)
Or ∠ABC and ∠DEF are supplementary.
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