Math, asked by sunainagautam61, 4 months ago

If the average of 7 consecutive odd number is
21, what is the difference between the smallest and
the largest number?
I​

Answers

Answered by pradeepthakur25892
0

Answer:

let the seven consecutive nos be x, x+1, x+2, x+3, x+4, x+5, x+6

Average = sum of all the nos / total numbers

21 = x +(x+1) +(x+2) +(x+3)+( x+4) +(x+5)+(x+6)/7

21 = 7x + 21/7

21 *7 = 7x +21

7x = 147 - 21

x = 126/7

x = 18

Largest no = x+6 = 18+6=24

smallest no. = 18

Answered by joshihimanshu1979
0

Answer:

12

Step-by-step explanation:

let the first number is x

so

x+x+2+x+4+x+6+x+8+x+10+x+12/7=21

so

x+x+2+x+4+x+6+x+8+x+10+x+12=21x7=147

=7x+42=147

7x=105

x=15

smallest number=15

largest number=15+12=27

27-15=12

ans->12

pls mark as brainliest

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