If the average of 7 consecutive odd number is
21, what is the difference between the smallest and
the largest number?
I
Answers
Answered by
0
Answer:
let the seven consecutive nos be x, x+1, x+2, x+3, x+4, x+5, x+6
Average = sum of all the nos / total numbers
21 = x +(x+1) +(x+2) +(x+3)+( x+4) +(x+5)+(x+6)/7
21 = 7x + 21/7
21 *7 = 7x +21
7x = 147 - 21
x = 126/7
x = 18
Largest no = x+6 = 18+6=24
smallest no. = 18
Answered by
0
Answer:
12
Step-by-step explanation:
let the first number is x
so
x+x+2+x+4+x+6+x+8+x+10+x+12/7=21
so
x+x+2+x+4+x+6+x+8+x+10+x+12=21x7=147
=7x+42=147
7x=105
x=15
smallest number=15
largest number=15+12=27
27-15=12
ans->12
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