If the average of two number are 46 and their product is 747. Fhe find their difference
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a+b/2 =46
a+b = 92
b = (92-a)
ab = 747
a(92-a) = 747
a^2 - 92a + 747 = 0
a^2 - 83a - 9a + 747 = 0
a(a - 83) - 9(a - 83) = 0
(a - 9).(a - 83) = 0
a = 9 or 83
if a = 9 then, b = 83
if a = 83 then, b = 9
Hence , the numbers are 9 and 83.
a+b = 92
b = (92-a)
ab = 747
a(92-a) = 747
a^2 - 92a + 747 = 0
a^2 - 83a - 9a + 747 = 0
a(a - 83) - 9(a - 83) = 0
(a - 9).(a - 83) = 0
a = 9 or 83
if a = 9 then, b = 83
if a = 83 then, b = 9
Hence , the numbers are 9 and 83.
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