If the average velocity of freely falling body is 7 metre per second then find the height at which it is released.
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work energy theorem
1/2mv^2=mgh
implies
v^2=2gh
49=2×10×h
h=2.45m
1/2mv^2=mgh
implies
v^2=2gh
49=2×10×h
h=2.45m
Answered by
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Answer:
2.45m
½mv² = mgh
implies,
v² = 2gh
49 = 2 × 10 × h
Height = 2.45m
Explanation:
Hence required height is 2.45m
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