Question

If the base and height of a parallelogram are 16cm and 9cm, respectively, then its area is______ cm^2​

Answer 1

$\Large{\underline{\underline{\bf{\red{Given}}}}}$

• Base of Parallelogram = 16cm
• Height of parallelogram = 9cm

$\Large{\underline{\underline{\bf{\red{Find\:out}}}}}$

• Area of parallelogram

$\Large{\underline{\underline{\bf{\red{Solution}}}}}$

As we know that

➞ Area of Parallelogram

➞ base × height

➞ 16 × 9

➞ 144cm²

$\Large{\underline{\underline{\bf{\red{Extra\: Information}}}}}$

• Area of rhombus = ½ × product of diagonals

• Area of trapezium = ½ × height × (sum of parallel sides)

• Area of rectangle = length × breadth

Answer 2

$\bf{\underline{\underline \green{Solution:-}}}$

$\frak\red{AnswEr}\begin{cases}\sf\blue{\underline{The \: area \: of \: the \: parallelogram \: = \: 144\:Cm^2 }}\end{cases}$

$\frak\red{Given}\begin{cases}\sf\red{\underline{The \: base \: of \: the \: parallelogram \: are \: 16\:Cm.}} \\ \sf\blue{\underline{The \: height \: of \: the \: parallelogram \: are \: 9\:Cm.}}\end{cases}$

$\frak\red{Need \: To \: Find}\begin{cases}\sf\red{\underline{The \: area \: of \: the \: parallelogram \: = \: ?}}\end{cases}$

$\bf{\underline{\underline \green{ExPlanation:-}}}$

$\underline\mathtt \orange{Formula\:used\:here:-}$

$\bigstar \: \boxed{ \sf \: Area \: of \: the \: parallelogram = Base \times Height }$

$\underline\mathtt \orange{Now,Putting\:the\: values:-}$

$\longrightarrow \sf \pink {Area \: of \: the \: parallelogram = 16 \times 9}$

$\longrightarrow \sf \pink {Area \: of \: the \: parallelogram = 144\:Cm^2}$

$\underline\mathtt \orange{Hence:}$

$\longrightarrow\small\orange{\underline {\boxed{\sf\green{ The \: area \: of \: the \: parallelogram \: is \: 144\: Cm^2.} }}}$

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$