Question

if the base of a right angled triangle is 15 cm and its hypotenuse is 25 CM, then find its area.

Answer 1

Answer:

$\textbf{Area of the triangle }=150\;cm^2$

Step-by-step explanation:

$\textbf{Given:}$

$\text{Base of the triangle (b) = 15 cm}$

$\text{Hypotenuse of the triangle = 25 cm}$

$\text{Let h be the height of the triangle}$

$\text{By pythagoras theorem, we get}$

$b^2+h^2=(\text{Hypotenuse})^2$

$15^2+h^2=(25)^2$

$h^2=625-225$

$h^2=400$

$h=20\;cm$

$\text{Area of the triangle }=\frac{1}{2}{\times}b{\times}h$

$\text{Area of the triangle }=\frac{1}{2}{\times}15{\times}20$

$\therefore\text{Area of the triangle }=15{\times}10$

$\textbf{Area of the triangle }=150\;cm^2$

Answer 2

Answer:

Base=15cm

Hypotenuse=25cm

Height=?

put Pythagoras theorem

(hypotenuse)sq = (base)sq + (height)sq

(25)sq = (15)sq + (h)sq

625=225+(h)sq

625-225 = (h)sq

400 = (h)sq

√400 = h

20= h

h=20cm

Area of the triangle = 1/2×base×height

Area of the triangle = 1/2 ×15×20

area of the triangle = 150cmsq

Answer= 150cmsq