if the base of a right angled triangle is 8cm and the hypotenous is 17cm. find its area.
Answers
Answered by
6
by using Pythagoras theorem we can find height of triangle
17^2 =8^2+ h^2
h^2= 289- 64
h=√225
h=15
now area of triangle is half time product of base length and height
area=1/2×base×height
area=1/2×8×15
=4×15
=60 cm sq
17^2 =8^2+ h^2
h^2= 289- 64
h=√225
h=15
now area of triangle is half time product of base length and height
area=1/2×base×height
area=1/2×8×15
=4×15
=60 cm sq
Undo:
plz mark as brainliest
Similar questions