P. The Perimeter of a triangle whose sides are 3x+1, 4x+2 and 5x. Q. Subtract 7x² - 5xy +9 from 9x²-8xy +5. R. The product of 2x(3x +5xy) S. Area of square of side 4x + 2y Match the above with the correct answers.(a)16x²+16xy+4y² (b)12x +3 (c)2x²-3xy-4 (d)6x²+10x²y
(4 Points)
Answers
Answer:
3x+1+4x+2+5x
=12x+3
12x=3
x=3÷12
x=0.5
3x+1=3×0.5+1=2.5
4x+2=4×0.5+2=4
5x=5×0.5=2.5
perimeter of triangle= 2.5+4+2.5
=9squnit
hope u like the ans
Step-by-step explanation:
Answer:
P. 12x + 3
Q. 2x² - 3xy - 4
R. 6x² + 10x²y
S. 16x² + 16xy + 4y²
Step-by-step explanation:
P.
We know that,
Perimeter is the sum of the sides of a polygon
Here, Let the sides of the Triangle be A, B, and C
then,
A = (3x + 1)
B = (4x + 2)
C = (5x)
Now,
Perimeter(P) = A + B + C
P = (3x + 1) + (4x + 2) + 5x
P = 3x + 1 + 4x + 2 + 5x
P = 3x + 4x + 5x + 1 + 2
P = 12x + 3
Q.
(9x² - 8xy + 5) - (7x² - 5xy + 9)
= 9x² - 8xy + 5 - 7x² + 5xy - 9
= 9x² - 7x² - 8xy + 5xy + 5 - 9
= 2x² - 3xy - 4
R.
(2x) × (3x + 5xy)
Using Distributive Property,
= (2x × 3x) + (2x × 5xy)
= 6x² + 10x²y
S.
If the side of a Square is 's' then, its Area = s²
s = (4x + 2y)
So,
Area = s² = (4x + 2y)²
Using the identity, (a + b)² = a² + 2ab + b²
(4x + 2y)² = (4x)² + 2(4x)(2y) + (2y)²
= 4²x² + 16xy + 2²y²
= 16x² + 16xy + 4y²
Thus,
Area of a square whose side is (4x + 2y) is (16x² + 16xy + 4y²)
Hope it helped and you understood it........All the best