Question

If the base of a triangle is 8.6 cm and height is 4.5 cm ,what is its Area?​

Answer 1

Given :

• Base of triangle is 8.6 cm.
• Height is 4.5 cm.

To find :

• Area

Solution :

$\boxed{\pmb{\tt Area \: of \: triangle = \dfrac{1}{2} \times base \times height}}$

$\tt \leadsto \dfrac{1}{2} \times 8.6 \times 4.5$

$\tt \leadsto \dfrac{38.7}{2}$

$\tt \leadsto 19.35$

$\bold{\therefore Area \: of \: triangle \: is \: 19.35 cm^{2}}$

Answer 2

Step-by-step explanation:

Question:-

If the base of the triangle is 8.6cm and height is 4.5cm,what is it's area ?

Answer:-

Given :-

• The given figure is a triangle.

• The base of the triangle is 8.6cm.

• The height of the triangle is 4.5cm.

To find :-

Area of the triangle

Process :-

As we all know that:-

$⇒Area \: of \: triangle \: = \frac{1}{2} \times Base \times Height$

Inserting the above value in the formula:-

$⇒Area = \frac{1}{2} × Base × Height \\ \\ ⇒Area = \frac{1}{2} \times 8.6 \times 4.5 \\ \\ ⇒Area = \frac{1}{2} \times \frac{86}{10} \times \frac{45}{10} \\ \\ ⇒Area = 19.35cm²$

Therefore,the area of the triangle is 19.35cm².

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★ More to know

Some more formulas:-

$• \: Area \: of \:scalene \: triangle = \frac{1}{2} × Base × Height \\ \\ • \: Perimeter \: of \: scalene \: triangle = a+b+c \\ \\ • \: Area \: of \: equilateral\: triangle = \frac{ \sqrt{3} }{4} × {Side}^{2} \\ \\ • \: Perimeter \: of \: isosceles \: triangle = 2a+b \\ \\ • \: Perimeter \: of \: equilateral \: triangle = 3× Side \\ \\ • \: Area \: of \: isosceles \: triangle = \frac{b {h}^{b} }{2}$

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Hope it helps you...

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