Question

if the bisector of angles Angle B and angle C of triangle ABC meet at O if angle A = 40 degree find angle BOC​

Answer 1

IN TRIANGLE ABC

angle A +angle B +angle C =180

We have angle A =60

Therefore angle C +angle B =180-60= 120

Now we have bisectors of angle C and angle B

Therefore if angle B and angle C measures 180

Their bisector would measure half of them

Because angle bisector =total angle /2

Therefore angle OBC and angle OCB would measure

120/2=60

Now in triangle angle BOC, angle OBC, angle OCB would measure 180

Angle BOC =180 - (angle OBC and angle OCB)

(angle OBC and angle OCB)=60

Angle BOC =180-60

= 120

Answer 2

Step-by-step explanation:

In △BOC,

∠BOC+∠OBC+∠OCB=180 (OB and OC bisect ∠B and ∠C respectively)

∠BOC+21∠B+21∠C=180

∠BOC=180−21(∠B+∠C)

∠BOC=180−21(180−∠A)

∠BOC=180−21(180−70)

∠BOC=180−90+35

∠BOC=125∘