If the bisector of the vertically angle of a triangle bisect the base,show that triangle is isosceles
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Answer:
ΔABC is isosceles
Step-by-step explanation:
Let say ABC is the triangle
& AD ia angle bisector
BD = CD given
Produce AD to E such that AD=DE & then join E to C.
now in ΔABD & Δ ECD
∠ADB = ∠EDC opposite angles
BD = CD
AD=DE drawn
=> ΔABD ≅ Δ ECD
=> AB = CE
& ∠BAD = ∠CED
∠BAD = ∠CAD = ∠BAC /2
=> ∠CED = ∠CAD
in ΔAEC
∠CED = ∠CAD
=> CE = AC
while AB = CE
=> AB = AC
=> ΔABC is isosceles
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