if the body goes from A to B with velocity V1 and returns to a with velocity V2 then
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Answered by
11
Now, let the distance between A & B be 'd'.
We're gonna use the formula, (Distance)=(Speed)(Time).
Time taken to go from A to B is t1=d/V1.
Time taken to come from B to A is t2=d/V2.
Now, you know that average velocity is (total distance)/(total time).
Then, V(average)=(2d)/(t1+t2)=. You get V(average)=2(V1)(V2)/(V1+V2)
Read more on Brainly.in - https://brainly.in/question/64065#readmore
We're gonna use the formula, (Distance)=(Speed)(Time).
Time taken to go from A to B is t1=d/V1.
Time taken to come from B to A is t2=d/V2.
Now, you know that average velocity is (total distance)/(total time).
Then, V(average)=(2d)/(t1+t2)=. You get V(average)=2(V1)(V2)/(V1+V2)
Read more on Brainly.in - https://brainly.in/question/64065#readmore
Answered by
5
Answer:
Average velocity V = 0
Explanation:
When it returns back, then the velocity will be 0 only
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