Chemistry, asked by dabodiya8343, 1 year ago

If the bond energies of H - H, Br - Br, and H-Br are 433, 192 and 364 kJ mol⁻¹ respectively, the \Delta H^0 for the reaction H_2(g) + Br_2(g) \rightarrow 2HBr(g) is
(a) – 261 kJ
(b) + 103 kJ
(c) + 261kJ
(d) – 103 kJ

Answers

Answered by Anonymous
0

The first is the right answer


hirokbora7: but how to do it
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