Question

if the breadth of a rectangle is one third of its length and perimeter is 32cm, find the length and breadth of a rectangle​

Answer 1

8x=32×3

8x=96

x=96/8

x=12 cm

length 12cm

breadth 12/3 =4 cm

Answer 2

Let ,

Length of a rectangle (l) = x

So , Breadth of a rectangle (b) = x/3

Given ,

Perimeter of rectangle = 32 cm

We know that , the perimeter of rectangle is given by

$\pink { \large \fbox{ \fbox{ \sf \: Perimeter \: of \: rectangle = 2(l + b)}}}$

Substitute the values , we obtain

$\sf \implies 32 = 2(x + \frac{x}{3} ) \\ \\ \sf \implies \frac{32}{2} = \frac{3x + x}{3} \\ \\ \sf \implies16 (3)= 4x \\ \\ \sf \implies 48 = 4x \\ \\ \sf \implies x = \frac{48}{4} \\ \\ \sf \implies x = 12$

Thus , length = 12 cm & breadth = 4 cm