Physics, asked by biniroychacko4843, 11 months ago

If the capacitance of a conductor carrying a charge of 8 C is 0.005 F, calculate its potential.

Answers

Answered by 7225karunya

5

Answer:

160v

Explanation:

q = 8 c

c = 0.005 F

q = cv

v = q/c

=8/0.005

v = 160v

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