Physics, asked by girijavyas, 7 months ago

if the capacitance of a nanocapacitor is measured in terms of a unit u made by combining the electric charge e bohr radius a0 Planck's constant h and speed of light c then
a) u = e^2h/a0
b) u = hc/e^2a0
c) u = e^2c/ha0
d) u = e^2a0/hc

Answers

Answered by gageyaf828
0

Answer:

c is the correct answer

Explanation:

I have solved

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