Question

if the capillary rise of water in a 2 mm diameter tube is 1.5 cm,the height of capillary rise in a 0.5 mm diameter tube in cm will be

Answer 1

Explanation:

Formation of shadows suggests that light travels in a vacuum straight line curved path none of these The third stage in the water treatment process is a physical process biological process chemical process none of these

Answer 2

Answer:

The capillary rise in a 0.5mm Diameter tube will be 6cm

Explanation:

The capillary rise in a tube(h) is given by

$h = \frac{2 T\cos θ}{rpg}$

Where,

h=Capillary rise

h=Capillary riseT=Surface tension

h=Capillary riseT=Surface tensionr=Radius of Tube

h=Capillary riseT=Surface tensionr=Radius of Tubeρ=Density of liquid

h=Capillary riseT=Surface tensionr=Radius of Tubeρ=Density of liquidg=Acceleration due to gravity

h=Capillary riseT=Surface tensionr=Radius of Tubeρ=Density of liquidg=Acceleration due to gravityθ=Contact Angle

In our question we are given relation in terms of diameter.Hence we can rewrite the formula in terms of diameter of the tube(D) instead of radius.

Therefore

$h = \frac{4 T\cosθ }{Dρg}$

From the given question,we observe that except

capillary rise(h) and Diameter of Tube(D), all the quantities are constant

Therefore

$h∝ \frac{1}{D} = > h_{1}D_{1} = h_{2} D_{2}$

$1.5 \times 2 = h_{2} \times 0.5 = > h_{2} = 6cm$

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