Question

18. In the adjoining figure, AE and BC intersect each other at point D. If ZCDE = 90°, AB = 5 cm, BD = 4 cm and CD = 9 cm, = find DE.

Answer 1

From right triangle ADB,

AD = √AB² - DB² = √5² - 4² = √25 - 16 = √9 = 3cm

Now. since two chords AE and BC intersects at D,

AD × DE = CD × DB

3 × DE = 9 × 4

3DE = 36

DE = 36/3

DE = 12cm

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