if the car moving at a speed of 144 km/hr would decelerate constantly at 5m/^2 in 5 seconds what would be its final velocity
Answers
Answered by
1
Given
u=0
v=144kmph=144×
18
5
=40m/s
t=20sec
We know,
v=u+at
40=a×20
a=2m/s
2
Now,
s=ut+
2
1
at
2
s=
2
1
at
2
=
2
1
×2×20
2
=400m
u=0
v=144kmph=144×
18
5
=40m/s
t=20sec
We know,
v=u+at
40=a×20
a=2m/s
2
Now,
s=ut+
2
1
at
2
s=
2
1
at
2
=
2
1
×2×20
2
=400m
Answered by
0
Given
u=0
v=144kmph=144×
18
5
=40m/s
t=20sec
We know,
v=u+at
40=a×20
a=2m/s
2
Now,
s=ut+
2
1
at
2
s=
2
1
at
2
=
2
1
×2×20
2
=400m
u=0
v=144kmph=144×
18
5
=40m/s
t=20sec
We know,
v=u+at
40=a×20
a=2m/s
2
Now,
s=ut+
2
1
at
2
s=
2
1
at
2
=
2
1
×2×20
2
=400m
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