if the centre of a circle is (4/3,-2)and one end of the diameter is (3,2).find the coordinate of the other. "let's see who's brain works here"
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Mid point formula is (x1+x2)/2 , (y1+y2)/2
Center is the midpoint of diameter
So, (x+3)/2 , (y+2)/2 = (4/3 , -2)
then (x+3)/2 = 4/3 and (y+2)/2 = -2
3(x+3) = 8 y+2 = -4
3x+9 = 8 y=-6
3x=-1
x= -1/3
therefore the other end is (-1/3,-6)
Center is the midpoint of diameter
So, (x+3)/2 , (y+2)/2 = (4/3 , -2)
then (x+3)/2 = 4/3 and (y+2)/2 = -2
3(x+3) = 8 y+2 = -4
3x+9 = 8 y=-6
3x=-1
x= -1/3
therefore the other end is (-1/3,-6)
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