if the centroid of the triangle in which A(a,b) B (b,c) C(c,a) is at the origin the calculate the value of a3 + b3 + c3
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Answer:
it centroid is origin
this implies
the coordinates of centroid is (0,0)
the formula of find centroid is
( (x1+x2+x3)/3 , (y1+y2+y3)/3 )
so
(x1 + x2 + x3)/3 = 0
ATQ
(a + b + c)/3 = 0
a+b+c = 0
a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
if we put a + b + c = 0
we get
a³ + b³ + c = 3abc
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