Question

If the circle (9x) ^2+(9y) ^2=16 cuts the x-axis at (a, 0) and (-a, 0) then a is

Answer 1

hey it is ur answer

Answer 2

Answer:

9x²+ 9y²=16 cuts on x-axis so y=0

step 1:

substitute (a,0)

9(a)²+9(0)=16

9a²+0=16

9a²=16

a²=16/9

a±4/3

step 2:

substitute (-a,0)

9(-a)²+9(0)=16

9a²+0=16

9a²=16

a²=16/9

a±4/3

therefore a= ±4/3