if the circumference of a circle and the perimeter of a square equal then
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If the circumference of a circle and the perimeter of a square are equal, then
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the square
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA)
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)Now, ratio of their areas,
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)Now, ratio of their areas,πr2 and a2
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)Now, ratio of their areas,πr2 and a2=> πr2 and (πr4)2 [From eq(i)]
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)Now, ratio of their areas,πr2 and a2=> πr2 and (πr4)2 [From eq(i)]=> πr2 and π2r24
If the circumference of a circle and the perimeter of a square are equal, then(A)Area of the circle =area of the square(B)noneofthese(C)Area of the circle>area of the square(D)Area of the circle<area of the squareA) Solution :Let the radius of the circle be r and side of the square be a.Then, according to question,2πr=4a=> a=2πr4=πr2 ----(i)Now, ratio of their areas,πr2 and a2=> πr2 and (πr4)2 [From eq(i)]=> πr2 and π2r24Therefore, Area of the circle > Area of the square.